Hi, yes. Because the first dimension of a is 4 and the last dimension of b is also 4. /// Jürgen On 03/17/2017 06:05 PM, enz...@gmx.com
wrote:
yes last dimension of a must be = to first dimension of b but thenx←1 2 3 4 y←1 3 3 3 x+.=y works On Fri, 17 Mar 2017 17:29:24 +0100 Juergen Sauermann <juergen.sauerm...@t-online.de> wrote:Hi, the number of columns in a must match the number of rows in b (or the other way around, I don't quite remember). Try: a+.=⍉b 3 0 0 0 0 0 3 0 0 0 0 0 3 0 0 0 0 0 3 0 0 0 0 0 3 /// Jürgen On 03/17/2017 05:17 PM, enz...@gmx.com wrote: Hi what am i missing here? a←b←5 3⍴⍳8 a=b +/a=b a+.=b length error |
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