I still don't think it's correct. It first says that
shortest-duration-space is set to 1.2 by default and on the
second line it says that the same property is set to 2.0 by
default.
In the actual implementation, you have
(shortest-duration-space . 2.0)
(spacing-increment . 1.2)
/Mats
Han-Wen Nienhuys wrote:
[EMAIL PROTECTED] writes:
In Section 4.6.3 "Horizontal Spacing", it says
"Normally, shortest-duration-space is set to 1.2, which is the width of a note head, and shortest-duration-space is set to 2.0, meaning that the shortest note gets 2 NHW (i.e. 2 times shortest-duration-space) of space. For normal notes, this space is always counted from the left edge of the symbol, so the shortest notes are generally followed by one NHW of space."
I guess that a number of the references to "shortest-duration-space" should be replaced by references to "spacing-increment" or some other property, but I don't dare try to correct this mess, since I'm not 100% certain about what you really mean.
no, it's correct. shortest-duration-space is wrongly named; it is a
factor. Space is
( log2( shortest-playing-duration/shortest-duration) + shortest-duration-space) * spacing-increment
-- ============================================= Mats Bengtsson Signal Processing Signals, Sensors and Systems Royal Institute of Technology SE-100 44 STOCKHOLM Sweden Phone: (+46) 8 790 8463 Fax: (+46) 8 790 7260 Email: [EMAIL PROTECTED] WWW: http://www.s3.kth.se/~mabe =============================================
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