[email protected] wrote in
<612664271.16313594.1760439377633.javamail.r...@zimbra33-e6.priv.proxad.\
net>:
|Denys Vlasenko <[email protected]>
|Steffen Nurpmeso <[email protected]>
|
|@Steffen :
| as far as algos are concerned and from what can be observed with \
| the "tri" script's outputs,
| it works fine ... [.]
| preferably though :-).
Hm. I have not looked since back then, and indeed, if i trim the
test script a bit due to >>>, yes, in fact output of bb equals
bash! Fascinating! I will have to look how he did it, it totally
escaped me. I only see one remaining difference in between my own
code and plain busybox / bash, and that is
# make this work with (ba)sh \
command -v shopt && shopt -s expand_aliases;\
alias p=printf;alias e=echo;alias s=export
s I1=10 I2=20;p "<$((I1+=I2+=I1+=I2))>";e "<$I1><$I2>"
s I1=10 I2=20;p "<$((I1+=I2+=I1+=I1))>";e "<$I1><$I2>"
which gives for my code
#?0|kent:tmp$ busybox.static sh t2.sh
<80><80><50>
<60><60><40>
and for bash and plain bb
#?0|kent:tmp$ bash t2.sh
shopt
<60><60><50>
<50><50><40>
...$ busybox sh t2.sh
<60><60><50>
<50><50><40>
Where a C proof (what i want) gives
$ cat t.c; tcc -run t.c
#include <stdio.h>
int main(void){
int I1=10, I2=20;
I1+=I2+=I1+=I2;
printf("<%d><%d>\n", I1,I2);
I1=10, I2=20;
I1+=I2+=I1+=I1;
printf("<%d><%d>\n", I1,I2);
return 0;
}
<80><50>
<60><40>
But that is only a nit!
Wow -- he really did get the "several times recursed" conditionals
right with the current code!?!?!? I really will have to look.
Thank you.
--steffen
|
|Der Kragenbaer, The moon bear,
|der holt sich munter he cheerfully and one by one
|einen nach dem anderen runter wa.ks himself off
|(By Robert Gernhardt)
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