Hi Paul,
The following below is the code I have used.
// OperatorOverLoadingInher.cpp : Defines the entry point for the console
application.
//
#include "stdafx.h"
class base1
{
int x , y;
public:
base1()
{
x=10;
y=20;
}
base1 operator + (base1 *obj)
{
this->x=obj->x+this->x;
this->y=obj->y+this->y;
return *this;
}
virtual void show()
{
cout<<x<<y;
}
};
class derived:public base1
{
int x,y;
public:
derived():base1()
{
x=50;
y=60;
}
void show1()
{
cout<<x<<y;
}
};
Now My doubt is as I have used Public inheritence , then I can use base
class public member functions with derived class object. At the same time I
should use the operator which I overloaded in base class in derived class. But
I am unable to use it. Could you please explain why it happens so..
Paul Herring <[EMAIL PROTECTED]> wrote:
On 2/14/07, Gopi Krishna Komanduri <[EMAIL PROTECTED]> wrote:
>
> Hi Frnds,
> Why overloaded operator won't work for derived calss when
we supply
> operator overloading method in base class and also we derived using
public. Can any
> one of you please suggest.
Can you supply code to demonstrate what you're trying to do? Your
explanation isn't too clear:
#include <iostream>
class base {
public:
void foo(){ std::cout << "base::foo()\n"; }
virtual void bar() { std::cout << "base::bar()\n"; }
};
class derived : public base {
public:
void foo(){ std::cout << "derived::foo()\n"; }
virtual void bar() { std::cout << "derived::bar()\n"; }
};
int main(){
base* b;
b = new derived;
b->foo(); // base::foo() expected - what you're seeing?
b->bar(); // derived::bar() expected - what you want?
return 0;
}
--
PJH
Aio, quantitas magna frumentorum est
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