ranjan kumar ojha <[EMAIL PROTECTED]> wrote:          #include<cstdio>
int main()
{
char *s="\12345s\n";
print("%d",sizeof(s));
return 0;
}

what will be output of above program and why ???? 
   
   
  hi friend,
  your program will give error because you declare a pointer as trying to 
assign a value to a pointer at the declaration time.
  its not valid and acceptable in C
  

---------------------------------
Yahoo! Answers - Get better answers from someone who knows. Tryit now.

[Non-text portions of this message have been removed]



         

       
---------------------------------
Be a better Heartthrob. Get better relationship answers from someone who knows.
Yahoo! Answers - Check it out. 

[Non-text portions of this message have been removed]

Reply via email to