titli_juit wrote:
> #include<stdio.h>
> int main()
> {
> int i=0;
> for(i=0;i<20;i++)
> {
> switch(i){
> case 0:i+=5;
> case 1:i+=2;
> case 5:i+=5;
> default : i+=4;
> break;}
>
> printf("%d,",i);
> }
>
> return 0;
> }
>
> the output is 16,21
>
> can you please explain how am i getting this output?
switch-case requires break statements before the next 'case' or the
logic falls through to the next case statement which executes...and so on...
So:
When i = 0, i = i + 5 + 2 + 5 + 4;
Thus:
i = 0 + 5 + 2 + 5 + 4 = 16
i (16) is printed out. The loop increments i by 1 (i.e. 17). Then the
switch-case executes. Since i is 17, the default is executed and i
becomes 21.
The actual output is '16,21,' (without quotes). You forgot a comma.
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