thank you very much for answering my query
________________________________
From: [email protected] [mailto:[EMAIL PROTECTED] On Behalf
Of titli_juit
Sent: Tuesday, November 13, 2007 9:33 AM
To: [email protected]
Subject: [c-prog] please help
Hi,
Initially i is 0 and hence in switch case statement, it hits case 0
a nd in the second loop it is 17 and hence it hits default which is 17
+4 = 21.
To avoid this we have to use break statements in each and every case
statements.
#include<stdio.h>
int main()
{
int i=0;
for(i=0;i<20;i++)
{
switch(i){
case 0:i+=5; i=5
case 1:i+=2; i=7
case 5:i+=5; i=12
default : i+=4; i=16, i = 17+4= 21
break;}
printf("%d,",i); 16 , 21
i=17
}
return 0;
}
the output is 16,21
can you please explain how am i getting this output?
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