--- In [email protected], "John Matthews" <[EMAIL PROTECTED]> wrote: > > So the value of the > pointer will be whatever was in memory before, which might be 0, but it > very much depends on your compiler/OS/what happened a bit earlier etc.
Adding a printf() in the OP's code, using gcc under linux: $ a.out s0.s1 = 0xa75ff4 Segmentation fault $ a.out s0.s1 = 0x24eff4 Segmentation fault Hope you didn't put too much money on it :-)
