On Sun, Nov 23, 2008 at 1:19 PM, John Matthews <[EMAIL PROTECTED]> wrote: > --- In [email protected], "John Matthews" <[EMAIL PROTECTED]> wrote: >> >> So the value of the >> pointer will be whatever was in memory before, which might be 0, but it >> very much depends on your compiler/OS/what happened a bit earlier etc. > > Adding a printf() in the OP's code, using gcc under linux: > > $ a.out > s0.s1 = 0xa75ff4 > Segmentation fault > $ a.out > s0.s1 = 0x24eff4 > Segmentation fault > > Hope you didn't put too much money on it :-) > >
okay what is the solution of this problem ???????/ HOW can I assign the variable which called "name"
