Chris Weimann wrote:
> I have written a function called OutStr, which is a scaled-down version
> of printf for a small embedded system:
>
> void OutStr(const char * format, ...);
>
> Now I want to write another function that uses this function to write to
> various output devices, like this:
>
> void OutStrDevice(int Device, const char * format, ...);
>
> How can I call OutStr from within OutstrDevice and pass the same
> parameters in ellipsis?
>
> This illustrates what I am trying to do:
>
> void OutStrDevice(unsigned int Device, const char * format, ...)
> {
> switch(Device)
> {
> case 1:
> // code enable device1 one here
> break;
> default:
> case 2:
> // code enable device2 one here
> break;
> }
> Outstr(format,?????); // <-- How do I do this?
> }
>
>
> Regards
>
> Chris
You can't (at least not in a Standard way). Grab the varargs and just
pass that. Take a look at any printf() implementation. printf() is
typically not the function you end up ultimately calling.
--
Thomas Hruska
CubicleSoft President
Ph: 517-803-4197
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