I think you have a typo
function admin_toggleactive($id = null){
if (!$id) return;
$this->layout = 'ajax';
$this->autoRender = false;
$this->Project->id = $id; // And not $this->id = $id
$project = $this->Project->read();
> -----Messaggio originale-----
> Da: [email protected]
> [mailto:[EMAIL PROTECTED] Per conto di [EMAIL PROTECTED]
> Inviato: venerdì 16 marzo 2007 7.44
> A: Cake PHP
> Oggetto: savefield woes
>
>
> Quick question:
>
> I have this function to toggle an 'active' field un a project model,
>
>
> function admin_toggleactive($id = null){
>
> $this->layout = 'ajax';
> $this->autoRender = false;
>
> if ($id) {
> $this->id = $id;
> }
> if (!$this->id) return;
>
> $project = $this->Project->read();
> if($project['Project']['active']=='1'){
> $this->Project->saveField('active','0');
> }
> else{
> $this->Project->saveField('active','1');
> }
>
> $this->data = $this->Project->read();
> $this->render('../elements/project_set_unset_active');
>
> }
>
> Now this wont work, the data returned to the element is the
> same data (without the field toggled). BUT if I replace this line
>
> $this->data = $this->Project->read();
>
> to
>
> $this->data = $this->Project->findById($id);
>
> the element will be rendered with the new data (the actual
> value of the toggled field).
>
> Why does this happen ? Is this the only way to work around this?
>
>
> >
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