If you look at it: http://api.cakephp.org/1.2/ajax_8php-source.html ,
the link method returns the output, it doesn't print.
On Dec 4, 2007 1:37 PM, Mike Digital Egg <[EMAIL PROTECTED]> wrote:
>
> Hi,
> I need to take some output from a helper and put it into a variable
> rather than echoing it to screen, is this possible with Cake 1.2?
>
> eg.
> Helper Function: links.php
> [code]
> function return_link() {
> $output = $this->Ajax->link(__('return_link',true),'/
> index',array('update' => 'pagecontent','loading' =>
> "loading();showMenu();",'complete' => "complete();"),null,false);
> return $output;
> }
> [/code]
> Page View
> [code]
> <?php $return_link = $links->return_link(); ?>
> [/code]
>
> Doing this prints the link to screen (which I don't want it to do).
>
> Any ideas?
>
> Cheers
>
> Mike
> >
>
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