Hi Dordo, You are right that the ajax->link method does not echo the result, but if you put it within a custom helper method it does. Not sure why but I just took it out of the helper and put it directly in the view and it has worked. I will try and work out why it doesn't work in the helper when I have some more time.
Thanks for the help it just kicked some wheels in my brain in to gear :) Cheers Mike On Dec 4, 5:49 pm, "Dardo Sordi Bogado" <[EMAIL PROTECTED]> wrote: > If you look at it:http://api.cakephp.org/1.2/ajax_8php-source.html, > the link method returns the output, it doesn't print. > > On Dec 4, 2007 1:37 PM, Mike Digital Egg <[EMAIL PROTECTED]> wrote: > > > > > Hi, > > I need to take some output from a helper and put it into a variable > > rather than echoing it to screen, is this possible with Cake 1.2? > > > eg. > > Helper Function: links.php > > [code] > > function return_link() { > > $output = $this->Ajax->link(__('return_link',true),'/ > > index',array('update' => 'pagecontent','loading' => > > "loading();showMenu();",'complete' => "complete();"),null,false); > > return $output; > > } > > [/code] > > Page View > > [code] > > <?php $return_link = $links->return_link(); ?> > > [/code] > > > Doing this prints the link to screen (which I don't want it to do). > > > Any ideas? > > > Cheers > > > Mike --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Cake PHP" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~----------~----~----~----~------~----~------~--~---
