For the given example, it looks to me like you'd do this in the view: if ($data['Apple']['color'] == 'red')
On Sat, May 23, 2009 at 9:59 AM, jakobjp <m...@jakobjp.net> wrote: > > I've read a few discussions about CakePHP returning objects vs. > arrays, and this is NOT intended to be such. I just have a question, > related to it: > > I used to have (i.e. "before CakePHP") objects like this: > > class Apple { > var $color; > var $sweet; > function __construct($id = false) { > if ($id) $this->load($id); > return $this; > } > function load($id) { > ... do something to load apple with `id` = $id from db ... > } > function isRed() { > if ($this->color == 'red') return true; > else return false; > } > } > > > In my code I would then often work like this: > > $apple = new Apple(123); > if ($apple->isRed()) echo 'Apple is red"; > else echo 'Apple is not red'; > > > Now my question: > Where would a function like isRed() be located in the the CakePHP-way? > > Since in Cake I don't have an object to call a model's method on, I am > not sure how to go about this... > > > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "CakePHP" group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~----------~----~----~----~------~----~------~--~---