Interesting stuff. I have been trying to write fat models and get away
from putting all the logic in the controller, but I was incorrectly
passing the 'active record' as a parameter! It always _felt_ wrong,
and now you have shown my the right way. At least I wasn't dumb enough
to pass the id to the model method and reread the record.
Thanks.
On May 25, 3:34 am, mark_story <mark.st...@gmail.com> wrote:
> You can still do this with models as well. Using read(), create(),
> and set() your model methods can access the 'active record' and
> manipulate it. so for example
>
> $this->Apple->id = 1;
> $this->Apple->read()
> if ($this->Apple->isRed()) {
> //do something
>
> }
>
> And your isRed method could look like
>
> function isRed($color = null) {
> if (!$color && isset($this->data['Apple']['red'])) {
> $color = $this->data['Apple']['color'];
> }
> return $colour == 'red';
>
> }
>
> -Mark
>
> On May 23, 9:59 am, jakobjp <m...@jakobjp.net> wrote:
>
> > I've read a few discussions about CakePHP returning objects vs.
> > arrays, and this is NOT intended to be such. I just have a question,
> > related to it:
>
> > I used to have (i.e. "before CakePHP") objects like this:
>
> > class Apple {
> > var $color;
> > var $sweet;
> > function __construct($id = false) {
> > if ($id) $this->load($id);
> > return $this;
> > }
> > function load($id) {
> > ... do something to load apple with `id` = $id from db ...
> > }
> > function isRed() {
> > if ($this->color == 'red') return true;
> > else return false;
> > }
>
> > }
>
> > In my code I would then often work like this:
>
> > $apple = new Apple(123);
> > if ($apple->isRed()) echo 'Apple is red";
> > else echo 'Apple is not red';
>
> > Now my question:
> > Where would a function like isRed() be located in the the CakePHP-way?
>
> > Since in Cake I don't have an object to call a model's method on, I am
> > not sure how to go about this...
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