I would try writing the form without using shorttags <?= and using <?php
echo instead.

I doubt this would fix your issue, I would say it isn't a jquery problem as
the html is generated by the server.

On 23 March 2011 23:58, arron <[email protected]> wrote:

> I am using a jquery plugin stepy which turns my long form into a
> wizard.
> My whole form is written to comply with the form helper
>
> example
>        <?php echo $form-
> >create('relate',array('id'=>'default','name'=>'submit'));?>
>            <?= $form->input('FirstOwner.fname');?>
>                <?= $form->input('FirstOwner.lname');?>
>                <?= $form->input('FirstOwner.first_owner_title');?>
> html output
>
>  <form id="default" name="submit" method="post" action="/online/
> relates/add"><fieldset style="display:none;"><input type="hidden"
> name="_method" value="POST" /></fieldset>
>
> the problem i am having is when i use the form helper to create the
> form id all of my  inputs in my filedsets  disappear
>
> if i just hard code the first line to create the form
>
> <form id="default" method="post" name="submit" action="">
> every thing works.
>
> my concern is that if i dont use the form helper to start the form i
> will vulnerable to sql injection
>
> if i leave the first line like this<form id="default" method="post"
> name="submit" action=""> will i be  vulnerable to sql injection?
>
> Does anyone no of a work around so i can use something on the lines of
> this
>   <?php echo $form-
> >create('relate',array('id'=>'default','name'=>'submit'));?>
>  ?
>
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-- 
Kind Regards
 Stephen

 http://www.ninjacodermonkey.co.uk

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