Soewandi Wirjawan wrote:
>
> if i have this
>
> char buffer[5];
> int temp[4];
>
> buffer[0] = 'A';
> temp[0] = 3;
> temp[1] = 1;
> temp[2] = 2;
> temp[3] = 2;
>
> and i do this: memcpy(buffer+1, &temp, sizeof(temp));
> will the buffer contain A3122? because that's the
> result that i wanted, and somehow i only got the A
> part ...
No, you can't do this with memcpy, because an integer takes more memory
than a character, on most systems, an integer takes 4 bytes, a character
only 1. So the array temp would have 16 bytes, buffer only 5. So you
would even copy more memory to buffer than it contains, very dangerous.
The best way to do what you want to do is with a for loop:
for (int i=0; i<4; ++i)
buffer[i+1] = temp[i];
And be careful that the integers in temp are not 128 or more. Or less
than -127.
--
Mark Van Peteghem
http://www.q-mentum.com -- easier and more powerful unit testing
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