memset which we used for intialinzation of array in c this work only for character not for integer and memcopy will wok same character not for intger
it may work in vc++
if u have
char buffer[5];
char temp[4];
buffer[0] = 'A';
temp[0] = B;
temp[1] = D;
temp[2] = E;
temp[3] = W;
temp[0] = B;
temp[1] = D;
temp[2] = E;
temp[3] = W;
and U do this: memcpy(buffer+1, &temp, sizeof(temp));
TheN buffer contain ABDEW
TheN buffer contain ABDEW
Soewandi Wirjawan <[EMAIL PROTECTED]> wrote:
if i have this
char buffer[5];
int temp[4];
buffer[0] = 'A';
temp[0] = 3;
temp[1] = 1;
temp[2] = 2;
temp[3] = 2;
and i do this: memcpy(buffer+1, &temp, sizeof(temp));
will the buffer contain A3122? because that's the
result that i wanted, and somehow i only got the A
part ...
thanks
--- Mark Van Peteghem <[EMAIL PROTECTED]>
wrote:
>
> soewandi_w wrote:
>
> >
> >
> > Can anybody explain to me how memcpy works? I
> tried to copy an int
> > array to a char array, here's how i did it:
> >
> > memcpy (char_array+1, &int_array,
> sizeof(int_array));
> >
> > the char array already has an element in the slot
> 0, but somehow,
> > the memcpy didn't work, it didn't copy the
> int_array part to the
> > char_array since when i tried to print it out, it
> only gave me the
> > char part ...
>
> memcpy simply copies bytes from one place in memory
> to another. How many
> bytes is given by the thrid argument. But in your
> code you write
> sizeof(int_array). How is int_array defined? If it
> is defined like int
> *int_array; then sizeof(int_array) is 4. If it is
> defined like int
> int_array[100]; then sizeof(int_array) is 400.
> Another thing, the second
> argument probably has to be int_array, not
> &int_array. Also remember
> that the third argument is the number of bytes, not
> the number of
> elements in your array.
>
> --
> Mark Van Peteghem
> http://www.q-mentum.com -- easier and more
> powerful unit testing>
>
>
>
>
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