Just use the Unmarshaller constructor that takes a class:
myUnmarshaller = new Unmarshaller(MyPhoneBook.class);
then to set the mapping:
myUnmarshaller.setMapping(mapping);
--Keith
Eryq wrote:
>
> I have an XML input stream which I want to unmarshall.
> Let's say it looks like this:
>
> <phone_book>
> <person number="555-1212"... />
> ...
> (about a million of these)
> ...
> <person ... />
> </phone_book>
>
> However, I want to explicitly provide the top-level
> object which corresponds to <phone_book>, rather than
> simply put a class name in the mapping file.
> I.e., what I want to do is have PhoneBook be an interface
> and do something like this (fantasy code marked by ###):
>
> PhoneBook pb = new SomePhoneBookImpl();
> pb.setSomeAttr(...);
> pb.loginToSomeDirectoryDB(...);
> pb.doSomeOtherStuff(...);
>
> Unmarshaller u = new Unmarshaller(myMappingFile);
> ### u.setRootObject(pb);
> u.unmarshall(myPhoneBookInfoSource);
>
> Is there any way to do this? The key point it that
> it must be done early; i.e., I need to be able to
> set up the PhoneBook object as I see fit before
> the unmarshaller starts invoking setXXX/addXXX methods
> on it to add the Person objects.
>
> TIA,
>
> --
> Eryq, http://www.zeegee.com/eryq
> WANTED: Schrodinger's Cat. Dead and/or Alive.
>
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