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Hi Qun

Because the 3 axes in orthorhombic space groups are non-equivalent but
in P212121 all are 2-fold screws, there are indeed 6 permutations for
assigning the axes (unless of course 2 of those are excluded from
consideration by some other information that you haven't mentioned).
These are klh and lhk in addition to the ones you mention.  For a
reference see International Tables Vol A, chap. 2, p. 21.  Normally the
standard permutation is decided by the order of the magnitudes of the
cell axis lengths, but presumably you are doing this because all 3 cell
lengths are very nearly equal (within experimental error including
possible non-isomorphism), otherwise what you are proposing wouldn't
make sense.  If for example only 2 of the cell lengths were nearly equal
this would reduce the number of feasible possibilities to only 2 (e.g.
hkl and hlk if a!=b=c).  The minus signs in the matrix are required to
maintain the same hand after transformation in the case that you have
measured anomalous differences.  Alternatively you could keep the
indices all positive and change the sign of the delta-anoms in the cases
where the permutation is non-cyclic (i.e. hlk, lkh and khl).  If you
have no anomalous data then it makes no difference whether you have the
minus signs or not, by Friedel's law the amplitudes of hkl and -h-k-l
are equal.

HTH!

-- Ian

> -----Original Message-----
> From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On 
> Behalf Of Qun Wan
> Sent: Tuesday, May 02, 2006 10:14 PM
> To: [email protected]
> Subject: [ccp4bb]: permute unit cell indices
> 
> ***  For details on how to be removed from this list visit the  ***
> ***          CCP4 home page http://www.ccp4.ac.uk         ***
> 
> 
> Hi,
> I Have a question about permuting crystal indices. When I compare two 
> crystal data sets to get crossR value to know how isomorphous they 
> are, I need to permute the indices of one of the crystal. Both of my 
> crystals have space group P212121. I was told to permute HKL to LKH, 
> HLK, and KHL. I do not have a clear mind the principle. For example, 
> by whole arrangement, there will be 6 possibilities for the 
> permutation. Why only four exist here? The second question is more 
> important: if I want to change from HKL to KHL, the new indices are 
> (0 -1 0    -1 0 0    0 0 -1), not (0 1 0  1 0 0   0 0 1).  Why there 
> is minus sign in the indices?
> 
> Could anyone recommend me one paper or book to read to solve 
> my puzzle?
> 
> Your help is greatly appreciated!
> 
> 

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