> -----Original Message-----
> From: [email protected] [mailto:[email protected]]
On
> Behalf Of Pavel Afonine
> Sent: 31 July 2009 03:39
> To: Jiamu Du
> Cc: [email protected]
> Subject: Re: [ccp4bb] question of extra high B factor
> 
>               with B~133 you uj is 3.7A which means that atom is all
over
> the place and meaningless

Hi

I've seen this connection between B and (presumably) the implied
positional uncertainty sigma(r) stated many times, and I would point out
that it's actually a non-sequitur.  The reason is that the RMS amplitude
u = sqrt(B/8pi^2) = 1.3 Ang for B = 133 Ang^2 does not equate to the
positional uncertainty.  Note that I'm not just pointing out the
arithmetic slip in the above calculation (how did you get 3.7 ?).  The
RMS amplitude pertains to the *instantaneous* atomic position arising
from thermal vibration/disorder, whereas of course with X-rays we
measure the *average* atomic position.

If you want an estimate of sigma(r) see this paper:

http://journals.iucr.org/d/issues/1999/11/00/jn0061/jn0061.pdf

Using equation 1 here and assuming a O atom (note that the positional
uncertainty depends on the no of electrons as well as B), I get sigma(r)
= 0.81 Ang for B = 133 Ang^2 (Z = 4.1 for O at s=0.3).  This of course
assumes it's valid to extrapolate the equation well beyond the range for
which it was derived! - but my point is that the temptingly
straightforward sigma(r) = sqrt(B/8pi^2) is the *wrong* equation to use!

In any case whatever value of sigma(r) (or B) you observe I would
dispute that this necessarily means that the atom isn't there, what
matters in the end is the electron density you see in the map.

Cheers

-- Ian



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