numbers".
Second, we know that this formula must hold true:
a + b + c + d = 40
Then I made the assumption that one of the weights must be equal to 1, so ..
a = 1
Then I saw the answer and stopped working on the problem.
Using 1, 3, 9, and 27 can you get all the numbers between 1 and 40?
1 = 1
2 = 3 - 1
3 = 3
4 = 3 + 1
5 = 9- 3 - 1
6 = 9 - 3
7 = ??
8 = 9 -1
9 = 9
10 = 9+1
11 = 9 + 3 -1
12 = 9 + 3
13 = 9 + 3 + 1
14 = ??
15 = ??
I'm going back to work now..
At 01:05 PM 11/3/2003 -0500, you wrote:
>Subject: Math Puzzle
>From: "Randell B Adkins" <[EMAIL PROTECTED]>
>Date: Mon, 03 Nov 2003 12:51:52 -0500
>Thread:
>http://www.houseoffusion.com/cf_lists/index.cfm/method=messages&threadid=10303&forumid=5#94330
>
>that is what I am asking. I understand that 1,3,9, and 27 have a common
>factor
>of 3 however not sure how one would have come up with that and if in
>fact
>there was an easy way of finding it out.
>
>This is truly a puzzle of the minds...
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