I lied - MOD only works with integers. You could then use Ounces = x - Int(x) or something like that.
Jim Davis President, http://www.depressedpress.com Webmaster, http://www.firstnight.org Webmaster, http://www.cfAdvocacy.org Senior Consultant, http://www.metlife.com > -----Original Message----- > From: Jim Davis [mailto:[EMAIL PROTECTED] > Sent: Saturday, June 07, 2003 6:11 PM > To: CF-Talk > Subject: RE: cf math ? > > The MOD operator will give you the remainder after division (for example > "10 MOD 3 = 1"). The Int() function will return a number with no > fraction. So in your case you could use > > x = YourEquation > > Pounds = Int(x) > > Ounces = (x MOD 1)/16 > > You could probably do all of that in one line, but it would be messy - > multiple lines of smaller chunks will make it easier to read. > > Jim Davis > President, http://www.depressedpress.com > Webmaster, http://www.firstnight.org > Webmaster, http://www.cfAdvocacy.org > Senior Consultant, http://www.metlife.com > > > > -----Original Message----- > > From: Dave Lyons [mailto:[EMAIL PROTECTED] > > Sent: Saturday, June 07, 2003 4:52 PM > > To: CF-Talk > > Subject: Re: cf math ? > > > > ok 1 more ? > > I forgot part of it > > > > what I am actually trying to do is make a form to estimate the weight > of a > > fish based upon length & girth. > > > > So the first part is ok ( I was leaving out a set of ()) > > > > so the first formula works > > and lets say that the fish is 29" long and 15" girth > > it would weight 8.16 pounds > > now the next part I don't know if I need a regex for or how to do it. > > > > I want to take the .16 from the weight (or variable c) > > and divide it by 16 to get the ounces > > so instead of the final answer being 8.16 pounds it would be 8 pounds > 2.56 > > ounces. > > > > I can see how I could do another form to do it but it would be nice to > > have > > it done all in 1 shot. But I don't know how to get rid of the pounds > part > > in > > the 2nd equation. > > > > any thoughts? > > > > thanks again:) > > Dave > > > > > > > > > > ----- Original Message ----- > > From: "Tony Gruen" <[EMAIL PROTECTED]> > > To: "CF-Talk" <[EMAIL PROTECTED]> > > Sent: Saturday, June 07, 2003 4:21 PM > > Subject: RE: cf math ? > > > > > > > This should get you on your way... > > > -------------------------------------------------- > > > <CFLOCK timeout="4"> > > > <CFSET A = 5> > > > <CFSET B = 3> > > > <CFSET D = 800> > > > <CFSET C = ((#A# * #A#) * #B#) / #D#> > > > </CFLOCK> > > > <html> > > > <head> > > > <title>Simple Math</title> > > > </head> > > > <body> > > > <cfoutput>#NumberFormat(C, '_____.__')#</cfoutput> > > > </body> > > > </html> > > > > > > -----Original Message----- > > > From: Dave Lyons [mailto:[EMAIL PROTECTED] > > > Sent: Saturday, June 07, 2003 12:34 PM > > > To: CF-Talk > > > Subject: cf math ? > > > > > > > > > i havent got to math functions yet but how would i do this in cf? > > > > > > > > > ((variableA x variableA) x variableB) / 800 = variableC > > > > > > thanks > > > > > > > > > > > > > > > ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~| Archives: http://www.houseoffusion.com/cf_lists/index.cfm?forumid=4 Subscription: http://www.houseoffusion.com/cf_lists/index.cfm?method=subscribe&forumid=4 FAQ: http://www.thenetprofits.co.uk/coldfusion/faq Get the mailserver that powers this list at http://www.coolfusion.com Unsubscribe: http://www.houseoffusion.com/cf_lists/unsubscribe.cfm?user=89.70.4
