Yeah it was a problem with my code although I could not identify it, it
works now.

PS. Do you know of any Java mailing lists where you can ask newbie questions
without getting snobbed?

-----Original Message-----
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Mark Mandel
Sent: Friday, 8 July 2005 1:04 PM
To: CFAussie Mailing List
Subject: [cfaussie] Re: [OT] Parse Integer out of string with Java

What does 'm.group()' return?

I'm also confused by when you say it returns 'nothing'.
Integer.parseInt() will either return a number, or it will throw an
exception, I've never seen it do any different.

Are you getting an exception?

Mark

On 7/8/05, Taco Fleur <[EMAIL PROTECTED]> wrote:
>  
>  
> 
> Sorry guys, I tried a Aussie Java Mailing list but got a message back from
> the moderator basically saying my question was to silly for them. 
> 
>   
> 
> So here goes in the hope someone here can answer this. 
> 
>   
> 
> I need to parse an integer out of string with a regEx. 
> 
>   
> 
> I tried: 
> 
>   
> 
>             Pattern p = Pattern.compile("([0-9]*)"); 
> 
>   
> 
>             Matcher m = p.matcher("BDAT 24 LAST\nEND"); 
> 
>             if (m.matches()) { 
> 
>                     byteToRead = Integer.parseInt(m.group(1)); 
> 
>                     System.out.println("byteToRead = " + byteToRead); 
> 
>             } 
> 
> But it gives me nothing, even when I use "." as the regEx. 
-- 
E: [EMAIL PROTECTED]
W: www.compoundtheory.com
ICQ: 3094740

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