On Tue, May 14, 2013 at 5:41 PM, Aaron Ballman <[email protected]>wrote:
> On Tue, May 14, 2013 at 8:34 PM, Richard Smith <[email protected]> > wrote: > > On Tue, May 14, 2013 at 4:07 PM, Charles Davis <[email protected]> > wrote: > >> > >> > >> On May 14, 2013, at 4:26 PM, Aaron Ballman wrote: > >> > > >> >> Do __sptr and __uptr get different manglings? > >> > > >> > They do: > >> > > >> > void func( int * __ptr32 p ) {} > >> > void func2( int * __ptr64 p ) {} > >> > > >> > PUBLIC ?func@@YAXPAH@Z ; func > >> > PUBLIC ?func2@@YAXPEAH@Z ; func2 > >> > > >> > Namely, the presence of E (rnk pointed this out previously). > >> He was asking about __sptr and __uptr :). They don't by the way: > >> > >> > cl /c test.cpp > >> [extraneous banner output omitted] > >> > dumpbin /symbols test.obj > >> [...] > >> 00F 00000010 SECT4 notype () External | ?func@@YAXPAH@Z (void > >> __cdecl func(int *)) > >> 010 00000020 SECT4 notype () External | ?func2@@YAXPAH@Z (void > >> __cdecl func2(int *)) > > > > > > Thanks. One more thing: > > > > template<typename T> void f(void **p, T *q) { *p = *q; } > > > > void *g(int *__ptr32 __sptr a) { > > void *result; > > f(&result, &a); > > return result; > > } > > void *h(char *__ptr32 __uptr a) { > > void *result; > > f(&result, &a); > > return result; > > } > > > > int main() { > > printf("%p\n", g((int *__ptr32 __sptr)0xdeadbeef)); > > printf("%p\n", h((char *__ptr32 __uptr)0xdeadbeef)); > > } > > > > Does one of these get sign-extended and the other one get zero-extended? > > The first is sign extended, and the second is zero extended in 64-bit. What happens if you change the two 'char's to 'int's?
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