For "equidistant point" please read "nearest equidistant point" as I just 
realised
that with two points only there are an infinite number of "equidistant points"

> From: [email protected]
> To: [email protected]
> Date: Fri, 30 Oct 2009 09:21:11 +0000
> Subject: [Jchat] Point equidistant to 3 or more other points
> 
> 
> Point equidistant to 3 or more other points   
>                       
>                       Hi!
>  
> 
> Not specifically related to J, a maths question really, but I will try to 
> code the solution in J!
>  
> 
> If there are 2 points, (x1 y1) and (x2 y2), the equidistant point is at the 
> midpoint at location ((x1+x2)/2) ((y1+y2)/2)
>  
> 
> eg if there are 2 points p and q at locations (1,2) and (3,0) the point 
> equidistant is at (2,1) - the midpoint m
>  
> 
>    y 
> 
> 4 |
> 
> 3 |
> 
> 2 |p
> 
> 1 |    m
> 
> _ |__q_______ x
> 
>   0 1 2 3 4
>  
> 
> Suppose there are more than 2 points? Is there a formula for working out the 
> point equidistant to the n points?
>  
> 
> eg if there are 3 points p q r at locations (1,2) (3,0) and (3,2), the
> point equidistant is still at (2,1), but I can't see a way of computing
> this from the figures.
>  
> 
>    y 
> 
> 4 |
> 
> 3 |
> 
> 2 |p--r
> 
> 1 |    m
> 
> _ |__q_______ x
> 
>   0 1 2 3 4                  NB hyphens are spaces-hotmail changes 2 spaces 
> to 1
>  
> 
> This is not a test question or homework crib - I am just interested in 
> mathematics!
>  
> 
> The thought occured to me and I just cant see a solution for the
> general case finding equidistant point of points (x1 y1) (x2 y2) (x3 y3) ...
> (xn yn)
> 
> ...and as for the 3D case (x1 y1 z1) (x2 y2 z2) (x3 y3 z3) ...
> (xn yn zn)......!!!!!!
>  
> 
> Thanks in advance!
> 
>                       
> 
>                       
>               
>                                                 
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