I agree. Take for example computing for all materials needed to manufacture a bulk order of t-shirts (also in manufacturing as Raw Material Requirement). Its basic arithmetic. Just find out how many materials are needed to make one t-shirt and multiply it by the number of orders by the buyer plus allowance ... and I use J for this.
The problem described was more complex than mine. :P -----Original Message----- From: [email protected] [mailto:[email protected]] On Behalf Of Oleg Kobchenko Sent: Saturday, October 31, 2009 8:41 AM To: Chat forum Subject: Re: [Jchat] Re High school algebra > J is a language concerned with problems MUCH more complex than yours. This is a misconception. > From: James C Field <[email protected]> > > I suggest you explore the internet and refer to printed versions of > basic geometry. The answer to your problem can be solved with PAPER and > PENCIL. > > J is a language concerned with problems MUCH more complex than yours. > > First... Draw a pencil diagram of the problem. > Second ... Draw a sketch reconsidering the initial parameters of the > problem. > Third...stop and think and the go to bed .... think again in the > morning. IT IS AMAZING HOW SMART YOU CAN BE IN THE MORNING! > > Richard Donovan wrote: > > Point equidistant to 3 or more other points > > > > Hi! > > > > > > Not specifically related to J, a maths question really, but I will try to > > code > the solution in J! > > > > > > If there are 2 points, (x1 y1) and (x2 y2), the equidistant point is at the > midpoint at location ((x1+x2)/2) ((y1+y2)/2) > > > > > > eg if there are 2 points p and q at locations (1,2) and (3,0) the point > equidistant is at (2,1) - the midpoint m > > > > > > y > > > > 4 | > > > > 3 | > > > > 2 |p > > > > 1 | m > > > > _ |__q_______ x > > > > 0 1 2 3 4 > > > > > > Suppose there are more than 2 points? Is there a formula for working out > > the > point equidistant to the n points? > > > > > > eg if there are 3 points p q r at locations (1,2) (3,0) and (3,2), the > > point equidistant is still at (2,1), but I can't see a way of computing > > this from the figures. > > > > > > y > > > > 4 | > > > > 3 | > > > > 2 |p--r > > > > 1 | m > > > > _ |__q_______ x > > > > 0 1 2 3 4 NB hyphens are spaces-hotmail changes 2 spaces > > to > 1 > > > > > > This is not a test question or homework crib - I am just interested in > mathematics! > > > > > > The thought occured to me and I just cant see a solution for the > > general case finding equidistant point of points (x1 y1) (x2 y2) (x3 y3) ... > > (xn yn) > > > > ...and as for the 3D case (x1 y1 z1) (x2 y2 z2) (x3 y3 z3) ... > > (xn yn zn)......!!!!!! > > > > > > Thanks in advance! > > > > > > > > > > > > > > _________________________________________________________________ > > New Windows 7: Simplify what you do everyday. Find the right PC for you. > > http://www.microsoft.com/uk/windows/buy/ > > ---------------------------------------------------------------------- > > For information about J forums see http://www.jsoftware.com/forums.htm > > > > > > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
