On Mon, Jun 28, 2010 at 9:54 PM, Alex Rufon <[email protected]> wrote: > I actually smiled when he wrote: > In general, when an Iverson-bracketed statement is false, we want it to > evaluate into > a "very strong 0," namely a zero so strong that it annihilates anything it is > multiplied by-even if > that other factor is undefined.
I wonder if there are many significant cases where this matters which do not involve 0 divided by 0? [I imagine there are, but I am drawing a blank when I try to think of them.] (I was also wondering about 1.17 where he apparently ignores negative numbers.) -- Raul ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
