Thanks joel, it's starting to make sense to me now.

I'd suggest more examples in the documentation explaining what this sync
parameter is and works so it's clearer

cheers

2017-06-04 0:53 GMT-03:00 Joel Matthys <jwmatt...@gmail.com>:

>
>
>
> there may be a default parameter, right? And that seems to be 0. If I have
> sync at "0", I hear no sound.
>
>
> I think "sync" is a poor keyword for this method. It has nothing to do
> with hard sync. Instead, it determines what to do with a UGen connected to
> its input.
>
> This:
> SinOsc a => SinOsc b => dac;
> 0 => b.sync; // the default
>
> results in no audio because ChucK is attempting to use the output of
> SinOsc a (which is of course a stream between -1 and 1) and using those
> values as the frequency parameter for SinOsc b. In other words, SinOsc b is
> playing at a frequency between -1 and 1.
>
> Here's a demonstration of how sync 0 can work:
>
> Phasor p => SinOsc b => dac;
> 1 => p.freq;
> 1000 => p.gain;
> 0.25 => b.gain;
> 4::second => now;
>
> Anyway, it doesn't seem like the sync parameter is able to do hard sync.
> It seemed that the "0" value would do that, but, as I said, I hear nothing.
>
>
> I think you're right; to do hard sync you have to manually check the
> Phasor and reset the oscillator phase. BTW, according to the source code,
> the .phase method ranges from [0-1).
>
> Phasor p => blackhole;
> SinOsc s => dac;
> 0.2 => s.gain;
> 440 => s.freq;
> 1 => p.freq;
>
> spork~ hardsync();
>
> while (true)
> {
>  second => now;
>  p.freq() + 1 => p.freq;
> }
>
> fun void hardsync()
> {
>   float prev;
>   while (true)
>   {
>       p.last() => float last;
>       if (last < prev) 0 => s.phase;
>       last => prev;
>       samp => now;
>   }
> }
>
>
>
> If phase input is linear in chuck, then the code from SuperCollider would
> be equivalent, but it is not. And even if it wasn't linear, I tried it with
> radian values and did not get the same results.
>
> I suspect it is not really doing phase modulation because it doesn't
> matter if I change the carrier frequency, and that is weird.
>
> well, I guess I'm repeating myself, sorry, just anxious in the hope of
> clarification.
>
> thanks
>
>
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