Shane,
The /12 represents the first 12 bits of a possible 32 of masking.
11111111.11110000.00000000.00000000
255 128+64+32+16=240
This mask is written as 255.240.0.0
37 is written as 00100101 (32+4+1)
Since the 2nd octet is 11110000, the 1's represent matching #'s ("static")
and the
0's represent any number.
the 4 bits of 37 stay the same (0010) this gives you a range of
0010 0000 - 0010 1111 = 32-47
You now have your network range
172.32.0.0 - 172.47.255.255
1st number is the network number, all 1's (the last) is your broadcast
number.
HTH,
Larry
Shane Stockman wrote:
> (1) If I have an address of 172.37.2.56/12 how would I work out the IP
> range , broadcast address ,subnet mask ,subnet address.?
> (2) What are the different config reg settings and what would they do ?
> e.g 0x2102 or 0X0101
>
> Thanks in advance
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