You want to consider the actual usable bandwidth of the link. If you
have a T-1 point to point circuit then use 1.544 Mbps. If you have a
256k fractional T-1 frame relay line with one PVC that has a CIR of
192Kbps, you might consider using 192K as your reference.
Remember that you don't necessarily need to have your individual
bandwidth allotments add up to 100% of the bandwidth of the link. You
can go higher or lower and it will stil work, it just might have some
other implications. For most purposes, Tony's example is the way to
go.
What might be confusing you is that there is no hard and fast rule to
choose your total byte count. It really depends on the specifics of
your situation and what you're trying to accomplish by adding CQ. For
most cases, though, I see no reason not to use the actual available
bandwidth as your reference.
Regards,
John
>>> "Cisco Lover" 8/29/01 12:39:42 AM >>>
Oopppsssssssss...
I think I am still failed to deliver my Q :(
My only confusion in this topic is that what Bandwidth we need to
consider
,when we do our lab scenerios..Like u consider here 64K...and divide it
as
per requirement..
Like for eg..I can see that IN FATKID LabA,they r saying that "As FR
link BW
is 64K ",and than diving 64K among different traffic.
On the other hand in another Lab(with normal serial link),they are
considering 32K as orignal BW and than playing with it..
As In usual Lab scenerios,we put 64K on Serial clock rates,Is that our
actual BW..
But When I used Sh interface S0, it shows BW=128K??????????
This is my ACTUAL CONFUSION????WHAT SHOULD BE THE VALUE OF BW TO USE?
Thanks for your help.
Cisco Lover
>From: "Tony Medeiros"
>Reply-To: "Tony Medeiros"
>To: [EMAIL PROTECTED]
>Subject: Re: A Custom Queuing Question [7:17622]
>Date: Wed, 29 Aug 2001 01:52:36 -0400
>
>Assume a 64k link. Custom queueing used "Byte counts" not bits for
it
>queue sizes. So divide a 64KiloBIT link by 8 and you get a 8K BYTES
per
>second link. Right ??
>
>So here is a quick and dirty queue-list I wrote for a 64KiloBIT link:
>
>queue-list 10 protocol ip 1 tcp www
>queue-list 10 protocol ip 2 tcp ftp
>queue-list 10 default 3
>queue-list 10 queue 1 byte-count 2000
>queue-list 10 queue 2 byte-count 4000
>queue-list 10 queue 3 byte-count 2000
>
>I made 3 queues and divided the 8k of BYTES that I can push through
it.
>Queue 1 does 2K bytes, Queue 2 does 4K bytes, and queue 3 does 2K
bytes.
>All add up to 8K bytes that we can push through the link.
>
>WWW traffic get 2k bytes or 25% of the link, FTP traffic get 4K bytes
or
>50%
>of the link, and anything else (default, the catch all) gets 2K bytes
or
>25%
>
>Does this help you understand? It's been a while since I wrote one of
>these
>so I hope I got all the syntax right.
>
>Tony M.
>#6172
>
>----- Original Message -----
>From: "Cisco Lover"
>To:
>Sent: Tuesday, August 28, 2001 9:41 PM
>Subject: A Custom Queuing Question [7:17622]
>
>
> > Hi Friends,
> >
> > Can any one here please explain what should be the"bandwidth Value"
if
>we
> > need to divide traffic by percentage ,using Custom queuing.
> >
> > As far as I know(IF Im right )during our lab,as we usually take
clock as
> > 64Kbps,then we need to divide this factor (64/8) among the
traffic.
> >
> > What about others????I m still confused..
> >
> > Hey!!!!!!!!Can you please solve my confusion.,.....(examples
preffered
>:)
> >
> >
> > Thanks.
> >
> > _________________________________________________________________
> > Get your FREE download of MSN Explorer at
>http://explorer.msn.com/intl.asp
_________________________________________________________________
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