Everybody's showing you the intelligent way, so I thought I'd try showing you my "Subnetting for dummies" method - Works for me- If you can follow the explanation, the calculation is childs play (Please excuse all incorrect network terms used for explanation (broken octets, chunks etc)):
"Say I have a network: 100.10.0.0 255.255.255.192" The fourth octet is what I call the broken one (the one which isn't 255 or 0) Take the value of that octet away from 256: 256-192 = 64 This is the size of the network "chunks". So (using multiples of 64 in the broken 4th octet) we have subnets as follows: 100.10.0.0 255.255.255.192 100.10.0.64 255.255.255.192 100.10.0.128 255.255.255.192 100.10.0.192 255.255.255.192 100.10.1.0 255.255.255.192 100.10.1.64 255.255.255.192 etc, etc These are all the network addresses for the ranges above. The broadcast addresses are obviously the last address in each network range (one less than the next network address). So they would be: 100.10.0.63 100.10.0.127 100.10.0.191 100.10.1.63 100.10.1.127 respectively. Hope the explanation helps. If it confuses, forget about it for now, but I'm sure it is the quickest way to work it out. Regards, Gaz ""Hunt Lee"" wrote in message [EMAIL PROTECTED]">news:[EMAIL PROTECTED]... > It would be great if someone can give me a hand on this: I know how to > calculate the number of subents and number of hosts per subent, but I'm > very confused about the Network address and the Broadcast address: > > Say I have a network: 100.10.0.0 255.255.255.192: > > 1) To work out the subnet: > > 100.10.0.0 is a Class A, so = /8 > > 255.255.255.192 = /26 > > Therefore, /26 - /8 = /14, > > The number of subnets = 2^14-2= 16382 > > 2) To work out the number of host: > > /32 - /26 = /6 > > The number of hosts = 2^6-2 = 62 hosts per subnets > > > Thanks so much for your help in advance. > > Best Regards, > Hunt Lee Message Posted at: http://www.groupstudy.com/form/read.php?f=7&i=23667&t=23632 -------------------------------------------------- FAQ, list archives, and subscription info: http://www.groupstudy.com/list/cisco.html Report misconduct and Nondisclosure violations to [EMAIL PROTECTED]
