The answer is NO.

While defining access-lists you have to use wildcards, meaning that the
range you are using must be blocks in 2^n (2 powered by n). Wildcards
difine the important and non-important bits is the IP address. They use
the same method and algorithm subnet masks use but in a reverse manner. In
a subnet mask you define the important bits ( the bits which you want to
exactly the same the IP address) with ONES, and the non-important bits
with ZEROs.
In wildcards, you define the important bits with zeros, and the
non-important bits with ones. For the same reson you cannot have a network
address with 37 hosts, you cannot define a access-list with a wildcard to
include 37 contigous addresses.
Here is an example: if you want to define an access-list for
11001101.01011101.1110001010.11010111 and you want all the bits to be same
but the last 3 bits your mask will be: 00000000.00000000.00000000.00000111
(0.0.0.7)
Hope this helps,
Hamid



Mahmood said:
> Thanx in advance dear friends,
> But is there any way to do this in one line?
>
> Thanx again
>
>
> ----- Original Message -----
> From: "Daniel Cotts"
> To: "'Mahmood'" ;
> Sent: Tuesday, June 11, 2002 7:17 PM
> Subject: RE: Access List Problem!! [7:46262]
>
>
>> Break it into pieces.
>> Deny the range of 192.168.32.0 to 192.168.32.31
>> Deny the range of 192.168.32.32 to 192.168.32.36
>> Deny the host 192.168.32.37
>> Since 192.168.32.0 is not a valid host address I see no problem with
>> including it.
>>
>> > -----Original Message-----
>> > From: Mahmood [mailto:[EMAIL PROTECTED]]
>> > Sent: Tuesday, June 11, 2002 10:02 AM
>> > To: [EMAIL PROTECTED]
>> > Subject: Access List Problem!! [7:46262]
>> >
>> >
>> > Hi,
>> > My question is taht : How Can I Deny this range: 192.168.32.1 to
>> > 192.168.32.37
>> > ?
>> >
>> > Thanks in advance
>> >
>> > Mahmood
> Nondisclosure violations to [EMAIL PROTECTED]




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