Hi Itay, The only decomposable object which is not a collection (as far as I know) is a String:
(seq "hello") ;=> (\h \e \l \l \o) But usually that's not what you want if you're traversing a data structure. If you're interacting with Java code that returns Iterators, Enumerables, or some weird collection that doesn't implement java.util.Collection, then all bets are off. For code related to traversing a structure, look at clojure.core/tree- seq and clojure.contrib.walk. -Stuart Sierra On Dec 17, 11:14 am, Itay Maman <itay.ma...@gmail.com> wrote: > Hi, > > I am trying to write a function that recursively traverses a given > object - applying a function to each node. Something along these > lines: > > (defn traverse [f os] > (f os) > (when (coll? os) > (doseq [o os] > (traverse f o)))) > > Although this fragment seems to be doing the job, I am not sure that > the underlying assumption - which is: everything that is not a > collection cannot be further decomposed - is true. Perhaps there's a > language construct that produces an object which is not a collection > but can be decomposed using some other mechanism? > (Seems highly unlikely, but I want to make sure that I am not missing > anything) > > Thanks, > -Itay > > I am --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en -~----------~----~----~----~------~----~------~--~---
