> I'm must be missing something obvious for the [s1 s2] case of union:
>
> Is it only that you've measured (conj s1 s2) to be faster when s2 is
> the smallest ?

Yes, that's it.  "conj" iterates through the second argument, and  
since count is O(1) for sets, it makes sense to always iterate through  
the smaller argument.  This makes a huge speed difference when you  
have one small set and one big set, as you can see in the timings I  
included.

-Jason





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