Can anyone explain this?
user> (def x {:foo :bar :foo :baz :foo :quux})
#'user/x
user> x
{:foo :bar, :foo :baz, :foo :quux}
user> (count (keys x))
3
user> (map x (keys x))
(:bar :bar :bar)
It's understandable that a literal map which includes the same key
twice with different values could return any one of the given values.
But I would expect the resulting map to have one key and one of the
values. Note:
user> (assoc {} :foo :bar :foo :baz :foo :quux)
{:foo :quux}
user> (conj {} [:foo :bar] [:foo :baz] [:foo :quux])
{:foo :quux}
user> (hash-map :foo :bar :foo :baz :foo :quux)
{:foo :quux}
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