On Wed, Aug 19, 2009 at 01:08, tmountain<tinymount...@gmail.com> wrote:
[snip]
>
> Also, this is
> a side question, but does anybody know if there's a faster (or better)
> way to compare two lazy sequences than the following?
>
> (defn seq-identical? [seq1 seq2]
> (zero? (compare (vec seq1) (vec seq2))))
>
A note on the naming: I wouldn't use "-identical?" as part of this
name, as that's not what you're asking:
(identical? x y) -- Tests if 2 arguments are the **same object**
On Wed, Aug 19, 2009 at 01:17, CuppoJava<patrickli_2...@hotmail.com> wrote:
>
> And = should work I think:
> (= [1 2 3] [1 2 3]) returns true.
>
Not only that, clojure's even smart enough to "do the right thing"
when the two arguments are lazy: In the case of unequal sequences, it
only evaluates as much of the sequence as is necessary to prove that
they are unequal. [
(defn =
"Equality. Returns true if x equals y, false if not. Same as
Java x.equals(y) except it also works for nil, and compares
numbers and collections in a type-independent manner. Clojure's
immutable data
structures define equals() (and thus =) as a value, not an identity,
comparison."
{:tag Boolean
:inline (fn [x y] `(. clojure.lang.Util equiv ~x ~y))
:inline-arities #{2}}
([x] true)
([x y] (clojure.lang.Util/equiv x y))
([x y & more]
(if (= x y)
(if (next more)
(recur y (first more) (next more))
(= y (first more)))
false)))
// Ben
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