Agh that makes sense, I thought I was going crazy but I guess it's  
obvious now you point it out... Thanks for the help :D

Gaz

Sent from my iPhone

On Nov 29, 2009, at 10:36 AM, Ahmed Fasih <wuzzyv...@gmail.com> wrote:

> Hi, without knowing much about what's going on, note that
>
> user=> (reduce + [15.00M 15.01M 3.00M 3.01M])
> 36.02M
> user=> (with-precision 3 (reduce + [15.00M 15.01M 3.00M 3.01M]))
> 36.0M
>
> So an intermediate step in the calculation is rounded down to 3
> decimals and that rounding error is carried through. So the "9M" with
> 3-precision would mean "9.00M".
>
> Amazing! It might be getting in your way here, but functions changing
> their operation because they were called via "with-precision" speaks
> to a flexibility that I've only seen in Lisps.
>
> On Nov 28, 10:27 pm, Gaz <gareth.e.jo...@gmail.com> wrote:
>> Hi, apologies if this is a silly question. Im having some confusion
>> with the following code:
>>
>> (with-precision 3 (/ 36.02M 4.00M))
>> 9.01M
>>
>> This is what i would expect. This however:
>>
>> (with-precision 3 (/ (reduce + [15.00M 15.01M 3.00M 3.01M])
>> 4.0M))
>> 9M
>>
>> Seems a bit odd? Or am I missing something obvious :(
>>
>> Thanks for any help.
>
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