Sorry, I think my reply got lost...

Inside deftype methods the symbol "Bar" is the name of the class. You
can use the constructor (Bar. (inc i)) instead. Again, note the "."
after Bar.

On Sat, Jan 2, 2010 at 1:23 PM, Konrad Hinsen
<konrad.hin...@fastmail.net> wrote:
> On 01.01.2010, at 23:56, Hugo Duncan wrote:
>
>>> I want to create a new instance of a deftype from inside one of its
>>> methods.
>>
>> I ended-up using extend-type for this case.
>
> That's probably the cleanest solution, but you lose the performance
> benefit of defining methods right in the type definition.
>
> After looking at the deftype code, I came up with the following
> solution:
>
> (defprotocol Foo
>   (foo [x]))
>
> (deftype Bar
>   [i]
>   Foo
>     (foo [] (new Bar (inc i))))
>
> (foo (Bar 0))
>
>
> Its drawback is relying on an undocumented feature: the value of Foo
> inside the methods is the class Foo being defined.
>
> Konrad.
>
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