gotta love well thought out libraries

Thanks Laurent

one more question, what if one was to attempt the reverse, ie:

( 1 2 3 4 5 6 7 8 9 10 11 12 14 15 16 )

into

( 1 2 3 4 (5 6 7 8) ((9 10 11 12)) (((13 14 15 16))) )

thanks, sorry just getting started with clojure/lisp

On Jan 19, 11:51 am, Laurent PETIT <laurent.pe...@gmail.com> wrote:
> Maybe you're in quest 
> ofhttp://richhickey.github.com/clojure-contrib/seq-utils-api.html#cloju...
> ?
>
> HTH,
>
> --
> Laurent
>
> 2010/1/19 Scott <sbuck...@gmail.com>:
>
> > i am utilizing parenthesis to represent a tree structure within a
> > genetic algorithm
>
> > I am trying to write a function that can strip all parenthesis such
> > that I can perform crossovers/mutations on the permutation.
>
> > Ex.
>
> > ( 1 2 3 4 (5 6 7 8) ((9 10 11 12)) (((13 14 15 16))) )
>
> > into
>
> > ( 1 2 3 4 5 6 7 8 9 10 11 12 14 15 16 )
>
> > the numbers are unique and can be in any order, and parenthesis can
> > occur anywhere in the representation [ another possible representation
> > is ( (5 6 7 8)  1 2 3 4 (((13 14 15 16))) ((9 10 11 12)) )  -- in this
> > case an operator must order the representation before applying the
> > removal of parenthesis]
>
> > so far I hacked something like:
>
> > (use 'clojure.contrib.str-utils)
>
> > (defn  genome-to-list [mytree]
> >  (apply list (re-gsub #"[()]*" "" (str mytree)  )
> > )
>
> > but I am sure there is a better option via regression, any ideas?
>
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