How about: (defn foo [coll] (apply concat (map (fn [[a b c d]] [c d a b]) (partition 4 coll))))
On Apr 11, 3:25 pm, Glen Rubin <rubing...@gmail.com> wrote: > I am working with a collection of sequences ...(e.g. > coll: > ((/f /b /c /4 /5 /6 /3 /6 /f /4 /3 /2 /4 /5 /7 /3 /6...) (/2 /b /c /4 / > 2 / > 6 /3 /7 /f /4 /3 /2 /4 /5 /7 /3 /6...)...) > > I want to rearange the sequence into groups of 4 where the later 2 > elements are moved to the front for example: > > (/f /b /c /4 /5 /6 /3 /6 /f /4 /3 /2 /4 /5 /7 /3 /6...) I want to > transform it as follows: > > (/c /4 /f /b /3 /6 /5 /6 /3 /2 /f /4....) > > I can break the collection of sequences up into groups of 4 as > follows: > > (map #(partition 4 %) coll) > > However I am having problems taking the resulting partitioned sequence > and further subdividing into groups of 2 before reversing the paired > groups order. -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en To unsubscribe, reply using "remove me" as the subject.