A single `for` will suffice:
(let [nums (range 1 4)]
(for [x nums y nums]
(* x y)))
If you wanted to build a map from pairs of elements of the input
collection to the matching values of your distance function, you could
do something like
(into {} (for [x xs y xs] [[x y] (distance x y)]))
You might want to replace [x y] with (hash-set x y) in the likely case
of distance being commutative.
Note also that if you're building the table to avoid recalculating the
distances, you might be better served by memoization; see (doc
memoize) at the REPL.
Sincerely,
Michał
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