Fantastic! Thanks again! On Nov 23, 3:50 pm, Benny Tsai <benny.t...@gmail.com> wrote: > Indeed there is :) > > http://clojuredocs.org/clojure_core/clojure.core/cycle > > On Nov 23, 12:37 am, Stefan Rohlfing <stefan.rohlf...@gmail.com> > wrote: > > > > > > > > > Hi Benny, > > > Your solution is much more elegant and flexible as my hacking of the > > core function! > > > How would you implement 'pad-padding' (I like this name) if every item > > of the padding should be repeated in order, not only the last one? > > > (defn pad-padding [padding] > > (concat padding (repeat padding))) > > > does not work because of the additional parentheses around 'padding'. > > > Is there a function that circles through the elements of a coll such > > as: > > > (take 10 (circle [1 2 3])) > > ;; (1 2 3 1 2 3 1 2 3 1) > > > Stefan > > > On Nov 23, 3:17 pm, Benny Tsai <benny.t...@gmail.com> wrote: > > > > Since (repeat) returns a lazy sequence, and partition will only take > > > as many as is needed, I think you don't even have to specify how many > > > times to repeat: > > > > user=> (partition 3 3 (repeat "a") [1 2 3 4 5 6 7]) > > > ((1 2 3) (4 5 6) (7 "a" "a")) > > > > And if the desired behavior is to repeat the last element of provided > > > padding as many times as necessary, you could do it with a little > > > helper function: > > > > (defn pad-padding [padding] > > > (concat padding (repeat (last padding)))) > > > > user=> (partition 4 4 (pad-padding ["a" "b"]) [1 2 3 4 5 6 7 8 9]) > > > ((1 2 3 4) (5 6 7 8) (9 "a" "b" "b")) > > > > On Nov 23, 12:05 am, Meikel Brandmeyer <m...@kotka.de> wrote: > > > > > Hi, > > > > > while not having looked at your code, partition does what you want: > > > > > user=> (partition 3 3 (repeat 3 "a") [1 2 3 4 5 6 7]) > > > > ((1 2 3) (4 5 6) (7 "a" "a")) > > > > user=> (partition 3 3 (repeat 3 "a") [1 2 3 4 5 6 7 8]) > > > > ((1 2 3) (4 5 6) (7 8 "a")) > > > > user=> (partition 3 3 (repeat 3 "a") [1 2 3 4 5 6 7 8 9]) > > > > ((1 2 3) (4 5 6) (7 8 9)) > > > > user=> (partition 3 3 (repeat 3 "a") [1 2 3 4 5 6 7 8 9 10]) > > > > ((1 2 3) (4 5 6) (7 8 9) (10 "a" "a")) > > > > > (Note: the 3 in repeat is not strictily necessary. 2 would be > > > > sufficient) > > > > > Sincerely > > > > Meikel
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