On Thu, Feb 3, 2011 at 4:33 PM, Base <basselh...@gmail.com> wrote:
> Thats the one!
>
> Now I just have to understand it...
>
> The first apply is throwing me a little.

Start with

(map foo [1 2 3] [4 5 6] [7 8 9])

That calls foo with the first elements of the collections (so, 1 4 7),
then again with the second (2 5 8), and then the third (3 6 9).

Now, if foo is vector the return values will be [1 4 7], [2 5 8], and
[3 6 9]. Which are the rows of your transposed matrix.

(apply map vector matrix)

does (map foo row1 row2 row3) in the case of a three-row matrix, for
instance, and more generally should extract the columns of any matrix.

(vec ...) wrapped around it converts the seq return value into a vector.

Note that (vec '(1 2 3)) => [1 2 3]; (vector 1 2 3) => [1 2 3], i.e.
(vec foo) = (apply vector foo).

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