Thanks. That works perfectly.
(ns test-csv
(:gen-class)
(:use clojure.contrib.command-line)
(:use clojure-csv.core))
(defn x1
[val1 val2]
(println val1 val2))
(defn process-file
"Process csv file and prints a column in every row"
[file-name]
(let [data (slurp file-name)
rows (parse-csv data)]
(dorun (map #(println ( nth % 11 nil)) rows ))))
(defn -main [& args]
(with-command-line args
"Get csv file name"
[[file-name ".csv file name" "resultset.csv"]]
[[file-name ".csv file name" 1]]
(println "file-name:", file-name)
(process-file file-name)))
On Jun 28, 9:01 am, Alex Robbins <alexander.j.robb...@gmail.com>
wrote:
> If you are trying to get the 6th row, you might use the "nth"
> function. It allows you to grab an element based on its index. That'd
> be better than tons of (next (next (next rows))) stuff.
>
> user=> (doc nth)
> -------------------------
> clojure.core/nth
> ([coll index] [coll index not-found])
> Returns the value at the index. get returns nil if index out of
> bounds, nth throws an exception unless not-found is supplied. nth
> also works for strings, Java arrays, regex Matchers and Lists, and,
> in O(n) time, for sequences.
>
> Alex
>
> On Tue, Jun 28, 2011 at 7:42 AM, octopusgrabbus
>
>
>
>
>
>
>
> <octopusgrab...@gmail.com> wrote:
> > Given this test program:
>
> > (ns test-csv
> > (:gen-class)
> > (:use clojure.contrib.command-line)
> > (:use clojure-csv.core))
>
> > (defn process-file
> > "Process csv file and prints first item in every row"
> > [file-name]
> > (let [data (slurp file-name)
> > rows (parse-csv data)]
> > (dorun (map #(println (first %)) rows))))
>
> > (defn -main [& args]
> > (with-command-line args
> > "Get csv file name"
> > [[file-name ".csv file name" 1]]
> > (println "file-name:", file-name)
> > (if file-name
> > (process-file "resultset.csv")
> > (process-file file-name))))
>
> > is it reasonable to write a recursive function that takes the lazy
> > sequence -- rows -- (returned from clojure-csv) and column numbers and
> > recurses until the appropriate column number is reached, or is it
> > better to build up a long series of expressions that would pull the
> > columns out?
>
> > For example, I believe I can pull out the second column by specifying
> > (first (next rows)), but it would look pretty awful to create a long
> > enough expression to get the 6th column in.
>
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