To add to Tassilo's answer, quoting blocks evaluation all the way down. So
even though I don't have the functions foo or bar defined:

user=> '(foo (bar))
(foo (bar))

There's no error, because neither is evaluated.

Chris

On 28 May 2012 18:58, Tassilo Horn <tass...@member.fsf.org> wrote:

> Maris <maris.orbid...@gmail.com> writes:
>
> > I have noticed that my functions don't get evaluated if they are
> > inside a list:
> >
> > '({:regex (re-pattern (str root-topic "/price-change//"))
> >                :metadata (get-metadata :price-change)
> >                :subscribe nil})
>
> That's because you've quoted (') the list and thus prevented any
> evaluation.  You probably want to use
>
> (list {:regex (re-pattern (str root-topic "/price-change//"))
>        :metadata (get-metadata :price-change)
>       :subscribe nil})
>
> Bye,
> Tassilo
>
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