you' are calling (apply 'foo '(1 2)), what you want is (apply foo '(1 2))
just call bar as
(bar (list foo 1 2))

2012/6/7 Alex Shabanov <avshaba...@gmail.com>

> I'm curious why the following form evaluates to 2:
>
> (defn foo [& more]
>   (println "foo(" more " )"))
>
> (defn bar [v]
>   (apply (first v) (rest v)))
>
> (bar '(foo 1 2))
>
> If the form (bar '(foo 1 2)) extended to, say, (bar '(foo 1 2 3 4)) the
> arity exception will be thrown.
> The behavior can be reproduced after picking another names for foo and/or
> bar functions.
>
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