> Given an annotation like this, and assuming that every? is > clojure.core/every? > > (defn blank? [^CharSequence s] (every? #(Character/isWhitespace %) s)) > > it seems as if it should be possible for the compiler to generate the > faster code. >
Yes, there is enough information for a compiler that is prepared in advance to handle such a special case. In a future version this may become true for this one case; however, I don't expect *predictably* good performance of HOFs/lazy seqs in the foreseeable future. If Clojure will still be a relevant language at the time of my retirement, by then it really could become a rock-solid performer :) -- You received this message because you are subscribed to the Google Groups "Clojure" group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
