What I was getting at there was that it seems like nil could mean a leaf
node with the value nil or the absence of leaf nodes, and the two
situations can't be distinguished.
On Dec 22, 2013 12:26 PM, "Lee Spector" <lspec...@hampshire.edu> wrote:

>
> On Dec 22, 2013, at 12:02 PM, Micha Niskin wrote:
>
> > Also, what about this:
> >
> > (loop [z (zip/seq-zip '((nil) 0))]
> >   (if (zip/end? z)
> >     :done
> >     (do (println (zip/node z))
> >       (recur (zip/next z)))))
> >
> > Which produces:
> >
> > ((nil) 0)
> > (nil)
> > nil
> > 0
> > :done
>
> I think that's actually fine. The nil is visited and printed as any other
> element would be. Maybe you expect nil to be handled specially? I'm not
> sure why, but in any event this is not the issue that I raised.
>
> The issue I was rasing is that, when traversing '(() 0) with zip/next, one
> should first visit the root, then (), and then 0. But what actually happens
> is that between then () and the 0 one lands on a non-existent nil node. So
> one ends up visiting 4 nodes when there are only 3, and the extra one is a
> nil.
>
> As I mentioned previously this leads to null pointer exceptions in my
> application, and the only ways around it that I see are recoding everything
> without zippers or some nasty special case hackery.
>
> It's also possible that I just don't understand something fundamental
> about zippers and that this is supposed to happen. But if that's not true
> -- if it's really a bug -- then it'd be great if this could be fixed.
>
> Thanks,
>
>  -Lee
>
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