It is working as designed.

If you do not want this, consider using sorted sets / sorted maps, where (=
s1 s2) implies (= (seq s1) (seq s2)).

Or, perhaps another programming language would be more to your liking.

Andy


On Sat, Feb 8, 2014 at 4:10 PM, Andy C <andy.coolw...@gmail.com> wrote:

>
> user> (= s1 s2)
>> true
>> user> (= (seq s1) (seq s2))
>> false
>>
>
> Thx. If a=b  then f(a) must = f(b). Something is broken here.
>
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